Question

ПОМОГИТЕ ПОЖАЛУЙСТА☺️ a)6^15*6^11/6^24
б)3^11*27/9^6

Answer 1

$\displaystyle\bf\\1)\\\\\frac{6^{15} \cdot 6^{11} }{6^{24} } =\frac{6^{15+11} }{6^{24} } =\frac{6^{26} }{6^{24} } =6^{26-24} =6^{2} =36\\\\\\2)\\\\\frac{3^{11}\cdot 27 }{9^{6} } =\frac{3^{11} \cdot 3^{3} }{(3^{2} )^{6} } =\frac{3^{11+3} }{3^{12} } =\frac{3^{14} }{3^{12} } =3^{14-12} =3^{2} =9$