Question

(17а^8-51 p^4k^2 )– (24 p^4k^2+9а^8)

Answer 1

$(17 {a}^{8} - 51 {p}^{4} {k}^{2} ) - (24 {p}^{4} {k}^{2} + 9 {a}^{8} )$

$17 {a}^{8} - 51 {p}^{4} {k}^{2} - 24 {p}^{4} {k}^{2} - 9 {a}^{8}$

$(17 {a}^{8} - 9 {a}^{8} ) + ( - 51 { p}^{4} {k}^{2} - 24 {p}^{4} {k}^{2} )$

$(17 - 9 ) { a}^{8} + ( - 51 { p}^{4} {k}^{2} - 24 {p}^{4} {k}^{2} )$

${(17 - 9)a}^{8} + ( - 51 - 24) {p}^{4} {k}^{2}$

$8 {a}^{8} + ( - 51 - 24) {p}^{4} {k}^{2}$

$8 {a}^{8} - 75 {p}^{4} {k}^{2}$