Question

помогите решить уравнение срочно

Answer 1

$\frac{1}{x^{2} } +\frac{4}{x} -12=0$

$\frac{1}{x^{2} } +\frac{4}{x} -12=0$

$\frac{1+4x-12x^{2} }{x^{2} }=0$

$1+4x-12x^{2} =0$

$-12x^{2} +4x+1=0$

$12x^{2} -4x-1=0$

$12x^{2} +2x-6x-1=0$

$2x(6x+1)-(6x+1)=0$

$(6x+1)(2x-1)=0$

$6x+1=0\\2x-1=0$

$x1=-\frac{1}{6} \\x2=\frac{1}{2}$