Question

ДОПОМОДІТЬ БАЛАГАЮ СЕМЕСТРОВА ​

Answer 1

$50b^3-2b=2b(25b^2-1)=2b(5b+1)(5b-1)$

$\displaystyle 50b^3-2b=2b(5b+1)(5b-1)=2\bigg(-\frac{1}{5}\bigg)\bigg(5\bigg(-\frac{1}{5}\bigg)+1\bigg)\bigg(5\bigg(-\frac{1}{5}\bigg)-1\bigg)=-\frac{2}{5}(-1+1)(-1-1)=-\frac{2}{5}\cdot 0 \cdot (-2)=0$