Question

Помогите пожалуйста, даю 50 балов. Задание на фото

Answer 1

$\displaystyle\bf\\1)\\\\\frac{16x-2}{14} -\frac{3x-4}{7} =2\\\\\\\frac{16x-2}{14}\cdot 14 -\frac{3x-4}{7} \cdot 14=2\cdot 14\\\\\\16x-2-(3x-4)\cdot2=28\\\\16x-2-6x+8=28\\\\10x+6=28\\\\10x=22\\\\\boxed{x=2,2}\\\\2)\\\\\frac{8x-5}{5} -\frac{12x-1}{6} =\frac{4x}{15} \\\\\\\frac{8x-5}{5}\cdot 30 -\frac{12x-1}{6} \cdot 30=\frac{4x}{15} \cdot 30\\\\\\(8x-5)\cdot6-(12x-1)\cdot 5=4x\cdot 2\\\\48x-30-60x+5=8x\\\\-12x-8x=25\\\\-20x=25\\\\\boxed{x=-1,25}$

$\displaystyle\bf\\3)\\\\\frac{17+2x}{3} -\frac{3x+1}{7} =5\\\\\\\frac{17+2x}{3}\cdot 21 -\frac{3x+1}{7}\cdot 21=5\cdot 21\\\\\\(17+2x)\cdot7-(3x+1)\cdot 3=105\\\\119+14x-9x-3=105\\\\5x=105-116\\\\5x=-11\\\\\boxed{x=-2,2}$