Question

ДАЮ 40 БАЛЛОВ
Решите пожалуйста 4,5,6,9 на листочке

Answer 1

Ответ:

См. ниже

Объяснение:

Answer 2

4)

$4 {m}^{4} {n}^{2} - 64 {m}^{4} {p}^{2} = 4 {m}^{4} \times {n}^{2} - 4 {m}^{4} \times 16 {p}^{2} = \\ = 4 {m}^{4} ( {n}^{2} - 16 {p}^{2} ) = 4 {m}^{4} (n - 4p)(n + 4p)$

5)

$3 {x}^{2} - 48xy + 192 {y}^{2} = 3( {x}^{2} - 16xy + 64 {y}^{2} ) = \\ = 3( {x}^{2} - 2 \times x \times 8y + (8y) {}^{2} ) = 3(x - 8y) {}^{2}$

6)

$- 75 {b}^{6} + 30 {b}^{4} - 3 {b}^{2} = - 3 {b}^{2} \times 25 {b}^{4} - 3 {b}^{2} \times ( - 10 {b}^{2} ) - 3 {b}^{2} \times 1 = \\ = - 3 {b}^{2} (25 {b}^{4} - 10b {}^{2} + 1) = - 3 {b}^{2} ((5 {b}^{2} ) {}^{2} - 2 \times 5 {b}^{2} \times 1 + {1}^{2} ) = \\ = - 3 {b}^{2} (5 {b}^{2} - 1) {}^{2}$

9)

$x + 4y + {x}^{2} - 16 {y}^{2} = x + 4y + ( {x}^{2} - (4y) {}^{2} ) = \\ = (x + 4y) + (x - 4y)(x + 4y) = (x + 4y)(1 + x - 4y)$