Question

Помогите, желательно сейчас

Answer 1

Ответ:

$\boxed{x =18}$

Пошаговое объяснение:

$4,5\div(47,375-(26\frac{1}{3} -x\times0,75)\times2,4\div0,88)=\frac{4}{11} \\ \\ \frac{9}{2} \div(\frac{379}{8} -(\frac{79}{3} -0,75x)\times\frac{12}{5} \div\frac{22}{25} )=\frac{4}{11} \\ \\ \frac{9}{2} \div(\frac{379}{8} -(\frac{79}{3} -0,75x)\times\frac{12}{5} \times\frac{25}{22} )=\frac{4}{11}\\ \\ \frac{9}{2} \div(\frac{379}{8} -(\frac{79}{3} -0,75x)\times6 \times\frac{5}{11} )=\frac{4}{11}\\ \\ \frac{9}{2} \div(\frac{379}{8} -(\frac{79}{3} -\frac{3}{4} x) \times\frac{30}{11} )=\frac{4}{11}$

$\frac{9}{2} \div(\frac{379}{8} -(\frac{790}{11} -\frac{45}{22} x) )=\frac{4}{11}\\ \\ \frac{9}{2} \div(\frac{379}{8} -\frac{790}{11} +\frac{45}{22} x)=\frac{4}{11}\\ \\ \frac{9}{2} \div(-\frac{2151}{88} +\frac{45}{22} x)=\frac{4}{11}\\ \\ \frac{9}{2} \div\frac{-2151+180x}{88}=\frac{4}{11}\\ \\ \frac{9}{2} \times\frac{88}{-2151+180x}=\frac{4}{11}\\ \\ 9 \times\frac{44}{9(-239+20x)}=\frac{4}{11}\\ \\ \frac{44}{-239+20x}=\frac{4}{11}\\ \\ 484=4(-239+20x)\\ \\ 121=-239+20x\\ \\ -20x=-239-121\\ \\ -20x=-360$
$\boxed{x =18}$