Question

поможіть пж срочно
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Answer 1

$(\frac{7}{12} -\frac{1}{6} ):\frac{25}{48} =(\frac{7}{12} -\frac{2}{12} ):\frac{25}{48} =\frac{5}{12} *\frac{48}{25} =\frac{4}{5}=0.8 \\\\(0.3-3.9):0.6=-3.6:0.6=-6$

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$(2x-3)^2-(2x-1)(2x+3)=-4\\4x^2-12x+9-(4x^2+6x-2x-3)=-4\\4x^2-12x+9-4x^2-6x+2x+3=-4\\4x^2-4x^2-12x-6x+2x=-9-3-4\\-16x=-16\\x=1$