Question

Поможіть будь ласка!!!!!!!!

Answer 1

$51\\1)\\8\frac{3}{7}-4\frac{2}{5}=8\frac{3\cdot5}{7\cdot5}-4\frac{2\cdot7}{5\cdot7}=8\frac{15}{35}-4\frac{14}{35}=4\frac{1}{35}\\\\2)\\6\frac{11}{15}-2\frac{7}{10}=6\frac{11\cdot2}{15\cdot2}-2\frac{7\cdot3}{10\cdot3}=6\frac{22}{30}-2\frac{21}{30}=4\frac{1}{30}$

$3)\\16\frac{17}{18}-2\frac{11}{12}=16\frac{17\cdot2}{18\cdot2}-2\frac{11\cdot3}{12\cdot3}=16\frac{34}{36}-2\frac{33}{36}=14\frac{1}{36}\\\\4)\\18\frac{13}{48}-5\frac{3}{64}=18\frac{13\cdot4}{48\cdot4}-5\frac{3\cdot3}{64\cdot3}=18\frac{52}{192}-5\frac{9}{192}=13\frac{43}{192}$

$52\\1)\\3\frac{1}{18}-\frac{1}{9}=3\frac{1}{18}-\frac{1\cdot2}{9\cdot2}=3\frac{1}{18}-\frac{2}{18}=2\frac{19}{18}-\frac{2}{18}=2\frac{17}{18}\\\\2)\\3\frac{17}{27}-2\frac{13}{18}=3\frac{17\cdot2}{27\cdot2}-2\frac{13\cdot3}{18\cdot3}=3\frac{34}{54}-2\frac{39}{54}=2\frac{88}{54}-2\frac{39}{54}=\frac{49}{54}$

$3)\\6\frac{3}{8}-2\frac{5}{9}=6\frac{3\cdot9}{8\cdot9}-2\frac{5\cdot8}{9\cdot8}=6\frac{27}{72}-2\frac{40}{72}=5\frac{99}{72}-2\frac{40}{72}=3\frac{59}{72}\\\\4)\\8\frac{11}{42}-5\frac{43}{126}=8\frac{11\cdot3}{42\cdot3}-5\frac{43}{126}=8\frac{33}{126}-5\frac{43}{126}=7\frac{159}{126}-5\frac{43}{126}=2\frac{116}{126}=2\frac{58}{63}$

$5)\\6\frac{7}{45}-4\frac{7}{20}=6\frac{7\cdot4}{45\cdot4}-4\frac{7\cdot9}{20\cdot9}=6\frac{28}{180}-4\frac{63}{180}=5\frac{208}{180}-4\frac{63}{180}=5\frac{145}{180}=5\frac{29}{36}\\\\6)\\9\frac{1}{21}-5\frac{16}{63}=9\frac{1\cdot3}{21\cdot3}-5\frac{16}{63}=9\frac{3}{63}-5\frac{16}{63}=8\frac{66}{63}-5\frac{16}{63}=3\frac{50}{63}$