Question

(3x^2+y^2)^2-x^2*(y-x)(x+y)
Привести в многочлен стандартного видв

Answer 1

$\displaystyle\bf\\(3x^{2} +y^{2} )^{2}-x^{2} \cdot(y-x)(x+y)=\\\\=(3x^{2} )^{2} +2\cdot 3x^{2} \cdot y^{2} +(y^{2} )^{2} -x^{2} \cdot(y^{2}-x^{2} )=\\\\=9x^{4} +6x^{2} y^{2} +y^{4} -x^{2} y^{2} +x^{4} =10x^{4}+5x^{2} y^{2} +y^{4}$

Answer 2

Ответ:

$10x^4 + 5x^2y^2 + y^4$

Объяснение:

$(3x^2+y^2)^2-x^2\cdot(y-x)(x+y)=\\\\3(x^2)^2+2\cdot 3x^2\cdot y^2+(y^2)^2-x^2(y-x)(y+2)=\\\\9x^4+6x^2xy^2+y^4-x^2(y^2-x^2)=\\\\9x^4+6x^2y^2+y^4-x^2y^2+x^4=\\\\10x^4 + 5x^2y^2 + y^4$