Question

А) (х-12)(х+81)=0
Б)(х+19)(х+6)=0
В) (5х-15)(х+7)=0

Answer 1

Пошаговое объяснение:

А)

(х - 12)(х + 81) = 0

1)

х - 12 = 0

х1 = 12

2)

х + 81 = 0

х2 = -81

Б)

(х + 19)(х + 6) = 0

1)

х + 19 = 0

х1 = -19

2)

х + 6 = 0

х2 = -6

В)

(5х - 15)(х + 7) = 0

1)

5х - 15 = 0

5х = 15

х = 15 : 5

х1 = 3

2)

х + 7 = 0

х2 = -7

Answer 2

A: (x - 12) (x + 81) = 0
x - 12 = 0
×1 = 12
x + 81 = 0
x2 = -81

Б: (x + 19)(x ÷ 6) = 0
x + 19 = 0
x1 = -19
x +6=0
x2= -6

B: (5x-15)(x + 7) = 0
5x - 15 = 0
5x = 15
x = 15:5
x1 = 3
x + 7=0
x2 =-7