Question

ПОМОГИТЕ С ДЗ ПОЖАЛУЙСТА Приведите многочлены к стандартному виду

Answer 1

Ответ:284.

1) 1/3m^3*n^2*p^2:( -2/3 m^2 *n^2*p^2)

1. 1/3:(-2/3)=1/3*(3/-2)= 1/-2

2. m^3: m^2= m^ 3-2= m^1=m

3.n^2:n^2=n^2-2= n^0=1

4.p^2:p^2=p^2-2=p^0=1

so the answer is = 1/-2*m*1*1=1/-2m

Объяснение:You have to divided each number which are the same.

Answer 2

1/3m^3*n^2*p^2:(-2/3 m^2
*n^2*p^2)
1. 1/3:(-2/3)=1/3* (31-2)= 1/-2
2.m^3:m^2=m^3-2=m^1=m
3.n^2:n^2=n^2-2=n^0=1
4.0^2:p^2=р^2-2=p^0=1
so the answer is = 1/-2*m*1*1=1/-2m