Question

ПОМОГИТЕЕ ПЖПЖПЖП СРОЧНО

Answer 1

Ответ:

$3\frac{4}{9} =\frac{3\times9+4}{9} =\boxed{\frac{31}{9} }\\\\ 5\frac{1}{3} =\frac{5\times3+1}{3} =\boxed{\frac{16}{3} }\\\\6\frac{2}{5} =\frac{6\times5+2}{5} =\boxed{\frac{32}{5} }\\ \\5\frac{5}{11} =\frac{5\times11+5}{11} =\boxed{\frac{60}{11} }\\ \\6\frac{2}{7} =\frac{6\times7+2}{7} =\boxed{\frac{44}{7} }\\ \\3\frac{1}{9} =\frac{3\times9+1}{9} =\boxed{\frac{28}{9} }\\ \\9\frac{3}{4} =\frac{9\times4+3}{4} = \boxed{\frac{39}{4} }\\\\11\frac{3}{5} =\frac{11\times5+3}{5} =\boxed{\frac{58}{5} }$

$13\frac{1}{2} =\frac{13\times2+1}{2} =\boxed{\frac{27}{2} }\\ \\13\frac{4}{9} =\frac{13\times9+4}{9} =\boxed{\frac{121}{9} }\\ \\5\frac{7}{8} =\frac{5\times8+7}{8} =\boxed{\frac{47}{8} }\\ \\4\frac{5}{7} =\frac{4\times7+5}{7} =\boxed{\frac{33}{7} }$