Question

помогите умоляю ..!!​

Answer 1

$\displaystyle\bf\\1)\\\\\frac{1}{2} \sqrt{400} =\frac{1}{2} \sqrt{20^{2} } =\frac{1}{2} \cdot 20=10\\\\2)\\\\\frac{1}{3} \sqrt{36} +\frac{2}{3} \sqrt{81} =\frac{1}{3} \sqrt{6^{2} }+\frac{2}{3} \sqrt{9^{2} } =\frac{1}{3} \cdot 6+\frac{2}{3} \cdot 9=\\\\\\=2+6=8$