Question

Разложить на множители (x+y)^2-x^4-y^4+2x^2y^2

Answer 1

(х+у)²-(x^4+y^4-2x²y²)=(x+y)²-(x²-y²)²=(x+y)²-(x-y)²(x+y)²=(x+y)²(1-(x-y)²)=
(x+y)²(1-x+y)(1+x-y)