Question

Помогите пожалуйста и скорее

Answer 1

$\displaystyle\bf\\\Big(\frac{7}{8} \Big)^{12} \cdot\Big(2\frac{1}{8} -1\frac{1}{4} \Big)^{10}= \Big(\frac{7}{8} \Big)^{12} \cdot\Big(1\frac{9}{8} -1\frac{2}{8} \Big)^{10}=\\\\\\=\Big(\frac{7}{8} \Big)^{12} \cdot\Big(\frac{7}{8} \Big)^{10}= \Big(\frac{7}{8} \Big)^{12-10} = \Big(\frac{7}{8} \Big)^{2} = \frac{49}{64}$