Question

100 баллов одно заданте, физика​

Answer 1

$\displaystyle n=\frac{\sin60^\circ}{\sin40^\circ} = \frac{\sin\alpha}{\sin22^\circ}\\\\\alpha = \arcsin\left(\frac{\sin60^\circ\sin22^\circ}{\sin40^\circ}\right)\approx30.3^\circ$