Question

(4-m)(m+4)< (2m-1)(m+3)-3m²-5m+40;​

Answer 1

Ответ:

$m\in R$

Объяснение:

$(4-m)(m+4) < (2m-1)(m+3)-3m^2-5m+40\\\\(4-m)(4+m) < 2m^2+6m-m-3-3m^2-5m+40\\\\16-m^2 < 2m^2+6m-m-3-3m^2-5m+40\\\\-m^2-2m^2-6m+m+3m^2+5m < 40-3-16\\\\0m < 21\\\\m\in R$