Question

³√y³ + y²-6y +8 = y;​

Answer 1

Пошаговое объяснение:

y^3 + y^2 - 6y + 8 = y

y^3 - y + y^2 - 6y + 8 = 0

y^3 + y^2 -7y +8 = 0

y^2 + 2y - 5

y^2 + 2y - 5 = 0

y = (-b ± √(b^2 - 4ac)) / (2a)

y = (-2 ± √(2^2 - 4(1)(-5))) / (2(1))

y = (-2 ± √(4 + 20)) / 2

y = (-2 ± √24) / 2

y = (-2 ± 2√6) / 2

y = -1 ± √6

y = -1 + √6

y = -1 - √6