Question

знайдіть область визначення функції:

y = $\frac{\sqrt{18-9x}}{7x+56}$

Answer 1

$\displaystyle\bf\\y=\frac{\sqrt{18-9x} }{7x+56} \\\\\\\left \{ {{18-9x\geq 0} \atop {7x+56\neq 0}} \right. \\\\\\\left \{ {{-9x\geq -18} \atop {7x\neq -56}} \right.\\\\\\\left \{ {{x\leq 2} \atop {x\neq -8}} \right.\\\\\\Otvet \ \ : \ \ D(y)=\Big(-\infty \ ; \ -8\Big)\cup\Big(-8 \ ; \ 2\Big]$