Question

СРОЧНО! ДАЮ 40 БАЛЛОВ

Answer 1

$\displaystyle \lim\limits_{x\rightarrow-2}(5+4x-2x^2) = 5+4(-2)-2(-2)^2=5-8-8=-11\\\\\displaystyle \lim\limits_{x\rightarrow4}\frac{x^2+64}{x+4} = \frac{16+64}{4+4} = 10\\\\\displaystyle \lim\limits_{x\rightarrow2}\frac{x^2-7x+12}{x^2-16} = \frac{4-14+12}{4-16}=-2/12 = -1/6\\\\\displaystyle \lim\limits_{x\rightarrow0}(\sqrt{4x+64x^2}-8x)=\sqrt{0}-0=0$