Question

подскажите пожалуйста​

Answer 1

Ответ:

$1)\ \frac{xy^6}{y^8}\\\\2)\ \frac{2ab^2}{6b^3}\\\\3)\ \frac{27mn}{12m^2n^2}\\\\4)\ \frac{22bcd}{30bd^7}$

Объяснение:

$1)\\\frac{x}{y^2}=\frac{x}{y^2}\cdot \frac{y^6}{y^6}=\frac{xy^6}{y^8}\\\\2)\\\frac{a}{3b}=\frac{a}{3b}\cdot \frac{2b^2}{2b^2}=\frac{2ab^2}{6b^3}\\\\3)\\\frac{9}{4m^2n}=\frac{9}{4m^2n}\cdot \frac{3mn}{3mn}=\frac{27mn}{12m^2n^2}\\\\4)\\\frac{11c}{15d^6}=\frac{11c}{15d^6}\cdot \frac{2bd}{2db}=\frac{22bcd}{30bd^7}$