Question

x² - 9x + 18 / x² - 9 = 0
с решением пж​

Answer 1

х ≠ 3; х ≠ -3

$\frac{ {x}^{2} - 3x - 6x + 18 }{(x - 3)(x + 3)} = 0 \\ \frac{x(x - 3) - 6(x - 3)}{(x - 3)(x + 3)} = 0 \\ \frac{(x - 3)(x - 6)}{(x - 3)(x + 3)} = 0 \\ \frac{x - 6}{x + 3} = 0 \\ x - 6 = 0 \\ x = 6$