Question

f(x) = 2x ^ 3 + 4x + 7 сос!!

Answer 1

$f(x) = 2x ^ 3 + 4x + cos7$

$f'(x) = \frac{d}{dx} (2x {}^{3} + 4x + cos7)$

$f'(x) = \frac{d}{dx} (2x {}^{3} ) + \frac{d}{dx} (4x) + (cos7)$

$f'(x) = 2 \times 3x {}^{2} + 4 + 0$

$Ответ:f'(x) = 6 {x}^{2} + 4$