Question

объясните пожалуйста как решить

(x^2-2x-1)^2+3x^2-6x-13=0

Answer 1

Ответ:

To solve the equation ( (x^2-2x-1)^2+3x^2-6x-13=0 ), we can follow these steps:

1. Expand the squared term by multiplying it with itself:

( (x^2-2x-1)(x^2-2x-1) + 3x^2-6x-13 = 0 ).

2. Simplify the expression:

( (x^4 - 4x^3 + 5x^2 + 4x + 1) + 3x^2 - 6x - 13 = 0 ).

3. Combine like terms:

( x^4 - 4x^3 + 8x^2 - 2x - 12 = 0 ).