Question

7
3(x")' .(yº)
4
5(x11)* .(y1)'
при х=25, у=15

Answer 1

Ответ:

3(x¹⁷)²×(y⁹)⁷ 3x³⁴y⁶³ 3x 3×25 75

----------------- = ----------- = ------- = -------- =----- = 1

5(x¹¹)³×(y¹⁶)⁴ 5x³³y⁶⁴ 5y 5×15 75