Question

(1) (3 + a)² + (a - 3)² - 18
2) (2m − n)² + n(4m – n)
3) 2n² + (5 + n) (5 – n) - (5 – n)²
4) (3a - b) (3a + b) - (3a + b)²
5) 2 (3a - b) + 3(4- 2a) + 2b

Answer 1

5)=6а-2b+12-6a+2b=12