Question

1. Теңдеулер жүйесін шешіңіз: х²-у+2=0
у-4х=7​

Answer 1

$\displaystyle \left \{ {{x^{2} -y+2=0} \atop {y-4x=7}} \right.$

$\displaystyle y=7+4x$

$\displaystyle x^{2} -(7+4x)+2=0\\x^{2} -7-4x+2=0\\x^{2} -4x-5=0\\D=16+20=36\\x_{1} =\frac{4+6}{2}=5 \\x_{2} = \frac{4-6}{2}=-1$

$\displaystyle y=7+4x\\y_{1}=7+4* 5=27\\y_{2}=7+4*(-1)=7-4=3$

(5;27)   (-1;3)