Question

Алгебра 7
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Answer 1

$\displaystyle\bf\\1)\\\\(3^{5} \cdot 3)^{3} \cdot(3^{4} )^{7}=(3^{5+1} )^{3} \cdot 3^{4\cdot 7} =(3^{6} )^{3} \cdot 3^{28} =\\\\\\=3^{6\cdot 3} \cdot 3^{28} =3^{18} \cdot 3^{28} =3^{18+28} =\boxed{3^{46}} \\\\2)\\\\3^{4} \cdot 3^{5} =3^{9} \ - \ verno\\\\3)\\\\2^{2} -(-3)^{2} =4-9=\boxed{-5}\\\\4)\\\\3^{4} -(-1)^{4} =81-1=\boxed{80}$