Question

1) arccos (−1) – arctg √3 ;​

Answer 1

Ответ:

$\frac{2\pi}{3}$

Объяснение:

$arccos( - 1) - arctg( \sqrt{3} ) = \\ = \pi - \frac{1}{3} \pi = \\ = \pi - \frac{\pi}{3} = \\ = \frac{3\pi - \pi}{3} = \\ = \frac{2\pi}{3}$