Question

Решите неравенство 2√7(12-5х)+3√3(5х-12)≥0.

Answer 1

$2 sqrt{7}(12-5x)+3 sqrt{3}(5x-12)=24 sqrt{7} -10 sqrt{7} *x+15 sqrt{3}*x-36 sqrt{3}=$

$x(15 sqrt{3}-10 sqrt{7}) geq 36 sqrt{3}-24 sqrt{7}$

$x geq frac{12(3 sqrt{3}-2 sqrt{7} ) }{5(3 sqrt{3}-2 sqrt{7}) }$

$x geq frac{12}{5}$

$x geq 2,4$

Ответ [2,4 +беск[

Answer 2

Большое спасибо .