Question

Представьте в виде дроби: а) x/2+y/3; б) c/4–d/12; в) a/b–b^2/a; г) 3/2x–2/3x; д) 5x/8y+y/4x; e) 17y/24c–25y/36c

Answer 1

Відповідь:

a) $\frac{x}{2} + \frac{y}{3} = \frac{x * 3}{2 * 3} + \frac{y * 2}{3 * 2} = \frac{3x}{6} + \frac{2y}{6} = \frac{3x + 2y}{6}$

б) $\frac{c}{4} - \frac{d}{12} = \frac{c * 3}{4 * 3} - \frac{d}{12} = \frac{3c}{12} - \frac{d}{12} = \frac{3c - d}{12}$

в)  $\frac{a}{b} - \frac{b^{2}}{a} = \frac{a * a}{b * a} - \frac{b^{2} * b}{a * b} = \frac{a^{2}}{ab} - \frac{b^{3}}{ab} = \frac{a^{2} - b^{3}}{ab}$

г) $\frac{3}{2x} - \frac{2}{3x} = \frac{3 * 3}{2x * 3} - \frac{2 * 2}{3x * 2} = \frac{9}{6x} - \frac{4}{6x} = \frac{9 - 4}{6x} = \frac{5}{6x}$

д) $\frac{5x}{8y} + \frac{y}{4x} = \frac{5x * x}{8y * x} + \frac{y * 2y}{4x * 2y} = \frac{5x^{2} }{8xy} + \frac{2y^{2} }{8xy} = \frac{5x^{2} + 2y^{2}}{8xy}$

е) $\frac{17y}{24c} - \frac{25y}{36c} = \frac{17y * 3}{24c * 3} - \frac{25y * 2}{36c * 2} = \frac{51y}{72c} - \frac{50y}{72c} = \frac{51y - 50y}{72c} = \frac{y}{72c}$