Question

ПОМОГИТЕ ПОЖАЛУЙСТА, ОЧЕНЬ СРОЧНО НАДО
АЛГЕБРА 8 КЛАСС​

Answer 1

Ответ:

Объяснение:

1) $\frac{a+7}{12}$+$\frac{a-4}{9}$=$\frac{3(a+7)+4(a-4)}{36}$=$\frac{3a+21+4a-16}{36}$=$\frac{7a+5}{36}$

2) $\frac{2b-7c}{6}$-$\frac{3b+2c}{15}$=$\frac{5(2b-7c)-2(3b+2c)}{30}$=$\frac{10b-35c-6b-4c}{30}$=$\frac{4b-39c}{30}$

3)$\frac{3x-2}{x}$-$\frac{3y-1}{y}$=$\frac{y(3x-2)-x(3y-1)}{xy}$=$\frac{3xy-2y-3xy+x}{xy}$=$\frac{x-2y}{xy}$

4) $\frac{6p+1}{p}$-$\frac{2p+8}{3p}$=$\frac{3(6p+1)-2p-8}{3p}$=$\frac{18p+3-2p-8}{3p}$=$\frac{16p-5}{3p}$

5)$\frac{5m-n}{14m}$-$\frac{m-6n}{7m}$=$\frac{5m-n-2(m-6n)}{14m}$=$\frac{5m-n-2m+12n}{14m}$=$\frac{3m+11n}{14m}$

6) $\frac{x+4}{11x}$ - $\frac{y-3}{11y}$ = $\frac{y(x+4)-x(y-3)}{11xy}$ = $\frac{xy+4y-xy+3x}{11xy}$ = $\frac{4y+3x}{11xy}$

7) $\frac{a+b}{ab}$ + $\frac{a-c}{ac}$ = $\frac{c(a+b)+b(a-c)}{abc}$=$\frac{ac+cb+ab+cb}{abc}$ = $\frac{a(c+b)}{acb}$ = $\frac{c+b}{cb}$

8) $\frac{2}{p^{2} }$ + $\frac{p-1}{p}$ = $\frac{2+p^{2}-p }{p^{2} }$

9) $\frac{k+4}{k}$ - $\frac{3k-4}{k^{2} }$ = $\frac{k(k+4)-3k+4}{k^{2} }$=$\frac{k^{2}+4k-3k+4 }{k^{2} }$ = $\frac{k^{2}+k+4 }{k^{2} }$

10) $\frac{x-y}{x^{3} }$ - $\frac{y-x^{2} }{x^{2} y}$ = $\frac{y(x-y)-x(y-x^{2} )}{x^{3} y}$=$\frac{xy-y^{2} -xy+x^{3} }{x^{3} y}$ = $\frac{x^{3}-y^{2} }{x^{3} y}$

11) $\frac{2m-3n}{m^{2}n }$ + $\frac{7m-2n}{mn^{2} }$ = $\frac{n(2m-3n)+m(7m-2n)}{m^{2}n^{2} }$ = $\frac{2mn-3n^{2} +7mn-2mn}{m^{2}n^{2} }$ = $\frac{n(7m-3n)}{m^{2}n^{2} }$ = $\frac{7m-3n}{m^{2} n}$

12) $\frac{c+d}{cd^{4} }$ - $\frac{c^{2}-8d }{c^{3}d^{4} }$ = $\frac{c^{2}(c+d)-d(c^{2} -8d) }{c^{3}d^{4} }$ = $\frac{c^{3} + c^{2}d - c^{2}d +8d^{2} }{c^{3}d^{4} }$ = $\frac{c^{3} +8d^{2} }{c^{3} d^{4} }$