Question

Наидите корень уравнения: 1) 1)5(3x+1,2) + x = 6,8; 2) 13-4,5y=2(3,7-0,5y), 4) 5,6-7y=-4(2y-0,9) +2,4. 5) 0,4x +3=0,2(3x+1)−x; 7) 3,4-0,6x=2x-(0,4x+1); 8) x-0,5=2(0,3x-0,2) = 3) 4(x+3,6)= 3x-1,4; 6)⁰ 0,8x-(0,7x+0,36) = 7,1;
ДАЮ 80 БАЛОВ СРОЧНО Буду очень благодарна
​

Answer 1

Ответ:

Объяснение:

5(3x+1.2)+x=6.8

15x+6+x=6.8

16x+6=6.8

16x=0.8

x= 16/0.8

x=0.05

13−4.5y=2(3.7−0.5y)

13−4.5y=7.4−y

−3.5y=−5.6

y≈1.6

5.6−7y=−4(2y−0.9)+2.4

5.6−7y=−8y+3.6+2.4

5.6−7y=−8y+6

5.6=−y+6

−0.4=−y

y=0.4

0.4x+3=0.2(3x+1)−x

0.4x+3=0.6x+0.2−x

0.4x+3=−0.4x+0.2

0.8x+3=0.2

0.8x=−2.8

x=−3.5

3.4−0.6x=2x−(0.4x+1)

3.4−0.6x=2x−0.4x−1

3.4−0.6x=1.6x−1

3.4=2.2x−1

4.4=2.2x

x=2

x−0.5=2(0.3x−0.2)

x−0.5=0.6x−0.4

−0.5=−0.4x−0.4

−0.4x=0.1

x=−0.25

4(x+3.6)=3x−1.4

4x+14.4=3x−1.4

x+14.4=−1.4

x=−15.8

0.8x−(0.7x+0.36)=7.1

0.8x−0.7x−0.36=7.1

0.1x−0.36=7.1

0.1x=7.46

x=74.6