Question

The solubility of NaCl at 25 °C is 36.0 g of the salt in 100 mL of water. The density of the saturated solution is 1.2 g/mL. Calculate the volume of the saturated solution required to prepare 100 mL of sodium chloride solution with ω(NaCl) = 5% and ρ = 1.034 g/mL​

Answer 1

Ответ:

Объяснение:

To calculate the volume of the saturated solution required to prepare the sodium chloride solution, we need to determine the mass of NaCl needed first.

The mass of NaCl in the 100 mL saturated solution can be calculated using the formula:

mass = volume × density

mass = 100 mL × 1.2 g/mL

mass = 120 g

The mass of NaCl in the 100 mL sodium chloride solution with ω(NaCl) = 5% can be calculated using the formula:

mass = volume × density

mass = 100 mL × 1.034 g/mL × 0.05

mass = 5.17 g

Now, we can use the ratio of the mass of NaCl in the saturated solution to the mass of NaCl in the desired solution to calculate the volume of the saturated solution needed:

volume of saturated solution = (mass of NaCl in desired solution / mass of NaCl in saturated solution) × volume of desired solution

volume of saturated solution = (5.17 g / 120 g) × 100 mL

volume of saturated solution = 4.307 mL

Therefore, the volume of the saturated solution required to prepare 100 mL of sodium chloride solution with ω(NaCl) = 5% and ρ = 1.034 g/mL is approximately 4.307 mL.