Question

Допоможіть буль ласка

Answer 1

Ответ:

7)

16/47*64 (42)/4+4=412/410-42-16

8)

(0.5a^2b^3)^3*(-2a^3b^2)^2

=0,125a^6b^9*4a^6b^4=0,5a^12b^13

0,5a^12b^13-3/2a^12b^13=0,5a^12b^13-1,5a^12 b^13--a^12b^13

9)

27a*b*c*

p = 3a²c²

27a*b*c*: 3a²c² = 9a*b*c*

27a*b*c

q=1/5a²b*

27a b c : 1/5a²b* = 135a*c*

Объяснение:

:)

Answer 2

Ответ:

№7.

$\frac{ {16}^{6} }{ {4}^{7} \times 64 } = \frac{ {4}^{12} }{ {4}^{7} \times {4}^{3} } = {4}^{2} = 16$

№8.

${(0.5 {a}^{2} {b}^{3} )}^{3} \times {( - 2 {a}^{3} {b}^{2} )}^{2} - \frac{3}{2} {a}^{12} {b}^{13} = - {a}^{12} {b}^{13} \\ 0.125 {a}^{6} {b}^{9} \times 4 {a}^{6} {b}^{4} - \frac{3}{2} {a}^{12} {b}^{13} = - {a}^{12} {b}^{13} \\ 0.5 {a}^{12} {b}^{13} - 1.5 {a}^{12} {b}^{13} = - {a}^{12} {b}^{13} \\ - {a}^{12} {b}^{13} = - {a}^{12} {b}^{13}$

№9.

$\frac{27 {a}^{8} {b}^{4} {c}^{6} }{3 {a}^{2} {c}^{2} } = 9 {a}^{6} {b}^{4} {c}^{4} \\ 27 {a}^{8} {b}^{4} {c}^{6} = 9 {a}^{6} {b}^{4} {c}^{4} p \\ \frac{9 {a}^{6} {b}^{4} {c}^{4} }{3 {a}^{2} {c}^{2} } = 3 {a}^{4} {b}^{4} {c}^{2} \\ 27 {a}^{8} {b}^{4} {c}^{6} = 3 {a}^{4} {b}^{4} {c}^{2} {p}^{2} \\ \frac{3 {a}^{4} {b}^{4} {c}^{2} }{3 {a}^{2} {c}^{2} } = {a}^{2} {b}^{4} \\ 27 {a}^{8} {b}^{4} {c}^{6} = {a}^{2} {b}^{4} {p}^{3} \\ \frac{ {a}^{2} {b}^{4} }{ \frac{1}{5} {a}^{2} {b}^{4} } = 5 \\ 27 {a}^{8} {b}^{4} {c}^{6} = 5 {p}^{3} q$