Question

ПОМОГИТЕЕ СРОЧНООО
ЗАДАНИЕ НА ФОТО​

Answer 1

Ответ:

снизу

Объяснение:

3. a) p(a) = p1(a) + p2(a)

p(a) = (3a - 4) + (11 - 3a)

p(a) = 3a - 4 + 11 - 3a

p(a) = (3a - 3a) + (-4 + 11)

p(a) = 0a + 7

p(a) = 7

б) p(a) = p1(a) - p2(a)

p(a) = (3a - 4) - (11 - 3a)

p(a) = 3a - 4 - 11 + 3a

p(a) = (3a + 3a) + (-4 - 11)

p(a) = 6a - 15

4. 3b^2 - a2b

3b^2 - a2b = b(3b - 2a)

5) -6ab + 2a^3 = ?

-6ab + 2a^3 = 2a^3 - 6ab

6) 5a(a^2 - 4a) - 4a(a^2 - 5a) = 5(-3)((-3)^2 - 4(-3)) - 4(-3)((-3)^2 - 5(-3))

= 5(-3)(9 + 12) - 4(-3)(9 + 15)

= 5(-3)(21) - 4(-3)(24)

= -315 + 288

= -27