Question

СРООООЧНО ДАЙТЕ ОТВЕТ ДАЯ 100 БАЛОВ!!

Answer 1

$\displaystyle\bf\\1)\\\\\frac{9+3\sqrt[3]{x} +\sqrt[3]{x^{2} } }{27-x} =\frac{9+3\sqrt[3]{x} +\sqrt[3]{x^{2} } }{3^{3} -(\sqrt[3]{x} )^{3} } =\\\\\\=\frac{9+3\sqrt[3]{x} +\sqrt[3]{x^{2} } }{(3-\sqrt[3]{x} )\cdot(9+3\sqrt[3]{x} +\sqrt[3]{x^{2} } )} =\frac{1}{3-\sqrt[3]{x} } \\\\2)\\\\\frac{\sqrt[4]{a} +\sqrt[4]{b} }{\sqrt{a} -\sqrt{b} } =\frac{\sqrt[4]{a} +\sqrt[4]{b} }{(\sqrt[4]{a} )^{2} -(\sqrt[4]{b} )^{2} } =$

$\displaystyle\bf\\=\frac{\sqrt[4]{a} +\sqrt[4]{b} }{(\sqrt[4]{a} -\sqrt[4]{b} )\cdot(\sqrt[4]{a} +\sqrt[4]{b} )} =\frac{1}{\sqrt[4]{a} -\sqrt[4]{b} }$