• Предмет: Алгебра
  • Автор: ilya2223137
  • Вопрос задан 3 месяца назад

Пожалуйста помогите как можно быстрее

Приложения:

Ответы

Ответ дал: olegandrejcenko846
1

Ответ:

1)

 \frac{8}{a}

2)

 \frac{4a + b + b {}^{2} }{7a}

3)

 \frac{4y}{4 - y {}^{2} }  -  \frac{y + 2}{y - 2}

4)

 \frac{a + 1}{2}

5)

 \frac{x + 4}{x - 4}  -  \frac{6x}{(x - 4) {}^{2} }

6)

 \frac{x - x {}^{2} }{56x - 28x {}^{2} - 28 }

7)

 \frac{30x - 1}{36x {}^{2} - 1 }

Объяснение:

1)

 \frac{2a + 5b}{ab}  -  \frac{2a - 3b}{ab}  =  \\  =  \frac{(2a + 5b) - (2a - 3b)}{ab}  =  \\  =  \frac{2a + 5b - 2a + 3b}{ab}  =  \\  =  \frac{8b}{ab}  =  \frac{8}{a}

2)

 \frac{a + b}{7a}  +  \frac{3a + b {}^{2} }{7a}  =  \\  =  \frac{a + b + 3a + b {}^{2} }{7a}  =  \\  =  \frac{4a + b + b {}^{2} }{7a}

3)

 \frac{y {}^{2}  + 8y}{4 - y {}^{2}  }  -  \frac{4y - 4}{4 - y {}^{2} }  =  \\  =  \frac{y {}^{2}  + 8y - (4y - 4)}{4 - y {}^{2} }  =  \\  =  \frac{y {}^{2} + 8y - 4y + 4 }{4 - y {}^{2} }  =  \\  =  \frac{y {}^{2} + 4y + 4 }{4 - y {}^{2} }  =  \\  =  \frac{4y}{4 - y {}^{2} }  +  \frac{y {}^{2}  + 4}{4 - y {}^{2} }  =   \\  = \frac{4y}{4 - y {}^{2} }  -  \frac{y {}^{2}  + 4}{ y { }^{2}  - 4}  =  \\  =  \frac{4y}{4 - y {}^{2} }  -  \frac{(y + 2)(y + 2)}{(y - 2)(y + 2)}  = \\  =   \frac{4y}{4 - y {}^{2} }  -  \frac{y + 2}{y - 2}

4)

 \frac{(2a - 1) {}^{2} }{6a - 6}  +  \frac{(a - 2) {}^{2} }{6 - 6a}  =  \\  =  \frac{(2a - 1) {}^{2} }{6a - 6}  -  \frac{(a - 2) {}^{2} }{6a - 6}  =  \\  =  \frac{(2a - 1) {}^{2}  - (a - 2) {}^{2} }{6a - 6}  =  \\  =  \frac{4a {}^{2} - 4a + 1 - (a {}^{2} - 4a + 4)  }{6a - 6}  =  \\  =  \frac{4a {}^{2}  - 4a + 1 - a {}^{2}  + 4a - 4}{6a - 6}  =  \\  =  \frac{3a {}^{2}  - 3}{6a - 6}  =  \\  =  \frac{3(a {}^{2} - 1) }{6(a - 1)}  =   \\  = \frac{a {}^{2} - 1 }{ 2(a - 1)}  =   \\  = \frac{(a - 1)(a + 1)}{2(a - 1)}  =  \\  =  \frac{a + 1}{2}

5)

 \frac{16 - 7x}{(x - 4) {}^{2} }  -  \frac{x - x {}^{2} }{(4 - x) {}^{2} }  =  \\  =  \frac{16 - 7x}{(x - 4) {}^{2} }  +  \frac{x - x {}^{2} }{(x - 4) {}^{2} }  =  \\  =  \frac{16 - 7x + x - x {}^{2} }{(x - 4) {}^{2} }  =  \\  =  \frac{16 - 6x - x {}^{2} }{(x - 4) {}^{2} }  =  \\  =  \frac{16 - x {}^{2} - 6x }{(x - 4) {}^{2} }  =  \\  =  \frac{16 - x {}^{2} }{(x - 4) {}^{2} }  -  \frac{6x }{(x - 4) {}^{2} }  =  \\  =  -  \frac{x {}^{2} - 16 }{(x - 4) {}^{2} }  -  \frac{6x}{(x - 4) {}^{2} }  =  \\  =  -  \frac{(x - 4)(x + 4)}{(x - 4) {}^{2} }  -  \frac{6x}{(x - 4) {}^{2} }  =  \\  =  \frac{x + 4}{x - 4}  -  \frac{6x}{(x - 4) {}^{2} }

6)

 \frac{3x}{4x - 4}  +  \frac{5x}{7 - 7x}  =  \\  =  \frac{3x(7 - 7x) + 5x(4x - 4)}{(4x - 4)(7 - 7x)}  =  \\  =  \frac{21x - 21x {}^{2}  + 20x {}^{2} - 20x }{28x - 28x {}^{2} - 28 + 28x }  =  \\  =  \frac{x - x {}^{2} }{56x - 28x {}^{2} - 28 }

7)

 -  \frac{5}{6x - 1}  -  \frac{6}{36x {}^{2} - 1 }  =  \\  =  -  \frac{5(6x + 1)}{(6x - 1)(6x + 1)}  -  \frac{6}{36x {}^{2} - 1 }  =  \\  =  \frac{5(6x + 1) - 6}{36x {}^{2}  - 1}  =  \\  =  \frac{30x + 5 - 6}{36x {}^{2} - 1 }  =  \\   = \frac{30x - 1}{36x {}^{2}  - 1}


ilya2223137: Спасибо большое
Mihals: Помогите пожалуйста https://znanija.com/task/53795944
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