Question

(3n-4)×(3n-4)=
(2x+y)×(2x+y)=
(m×0,75n)×(m-0,75n)=

Answer 1

$(3n-4)*(3n-4)=9n^2-12n-12n+16=9n^2-24n+16$
$(2x+y)*(2x+y)=4x^2+2xy+2xy+y^2=4x^2+4xy+y^2$