Question

Помогите решить пример

Answer 1

Ответ:

$\frac{2 {x}^{2} + 7x - 4 }{ {x}^{2} + 6x - 2} = 1 \\ 2 {x}^{2} + 7x - 4 = {x}^{2} + 6x - 2 \\ {x}^{2} + 6x - 2≠0 \\ \\ {x}^{2} + x - 2 = 0 \\ d = 1 - 4 \times ( - 2) = 1 + 8 = 9 \\ \sqrt{d} = \sqrt{9} = 3 \\ x1 = \frac{ - 1 - 3}{2} = \frac{ - 4}{2} = - 2 \\ x2 = \frac{ - 1 + 3}{2} = \frac{2}{2} = 1 \\ \\ {x}^{2} + 6x - 2≠0 \\ d = 36 - 4 \times ( - 2) = 36 + 8 = 44 \\ \sqrt{d} = \sqrt{44} = \sqrt{4 \times 11} = 2 \sqrt{11} \\ x1≠ \frac{ - 6 - 2 \sqrt{11} }{2} = \frac{ 2( - 3 - \sqrt{11}) }{2} = - 3 - \sqrt{11} \\ x2≠ \frac{ - 6 + 2 \sqrt{11} }{2} = \frac{2( - 3 + \sqrt{11)} }{2} = - 3 + \sqrt{11}$

х =-2;1

их сумма:

1-2=-1

ответ -1