Question

Помогите сделать
1) (x²-4) × 2x/(x+2)²
2) 6a/x²-x × 2x/(x+2)²
3) x²-16/x³-3x² × x²-9/x²+4x

Answer 1

Ответ:

1) (x² - 4) × 2x / (x + 2)² = 2x(x - 2)(x + 2) / (x + 2)(x + 2) = 2x(x - 2) / (x + 2)

2) 6a / (x² - x) × 2x / (x + 2)² = (6a * 2x) / ((x² - x)(x + 2)²)

3) (x² - 16) / (x³ - 3x²) × (x² - 9) / (x² + 4x) = [(x + 4)(x - 4)] / [x²(x - 3)] × [(x + 3)(x - 3)] / [x(x + 4)] = (x - 4)(x + 3) / (x - 3)