Question

Знайти W (Cu), W(O) i W(H) в сполуці (Cu(O H))2​

Answer 1

Mr(Cu(OH)2) = Ar(Cu) * N(Cu) + Ar(O) * N(O) + Ar(H) * N(H) = 64 * 1 + 16 * 2 + 1 * 2 = 98;

ω(Cu) = N(Cu) * Ar(Cu) * 100% / Mr(Cu(OH)2) = 1 * 64 * 100% / 98 = 65,31%;

ω(O) = N(O) * Ar(O) * 100% / Mr(Cu(OH)2) = 2 * 16 * 100% / 98 = 32,65%;

ω(H) = 100% - ω(Cu) - ω(H) = 100% - 65,31% - 32,65% = 2,04%.

Answer 2

Ответ:

Объяснение:

Mr(Cu(OH)2) = Ar(Cu)  + Ar(O) * 2 + Ar(H) * 1 =  64 * 1 + 16 * 2 + 1 * 2 = 98

w(Cu) =Ar(Cu) * n / Mr(Cu(OH)2) * 100% = 64/98 * 100% = 65,31%

w(O) = Ar(O) * n / Mr(Cu(OH)2) * 100% = 16 * 2/ 98 * 100% = 32,65%

w(H) = Ar(H) * n / Mr(Cu(OH)2) * 100% = 1 * 2/98 * 100% = = 2,04%