Question

интеграл от 1 до 4 (3-2x)dx​

Answer 1

Ответ:

int from 1 to 4 (3-2x)dx

Объяснение:

you need to know integral xdx= x^(1+1)/(1+1)

and integral adx = ax. So your question int from 1 to 4 (3-2x)dx=3x-2*(x^2)/2=3x-x^2 then x=4 3*4-4^2=12-16=-4 and x=1

3*1-1^2=3-1=2 then -4-2=-6 Answer:-6