Question

алгебра, помогите 90 балов. 3 задание​

Answer 1

$\displaystyle\bf\\+\left \{ {{x^{2} +y^{2} =8} \atop {x^{2} -y^{2} =0}} \right. \\--------\\x^{2} +y^{2} +x^{2} -y^{2} =8+0\\\\2x^{2} =8\\\\x^{2}=4 \\\\x_{1} =-2 \ \ ; \ \ x_{2} =2\\\\y^{2} =8-x^{2} =8-4=4\\\\y_{1} =-2 \ \ ; \ \ y_{2} =2\\\\Otvet \ : \ (-2 \ ; \ -2) \ , \ (-2 \ ; \ 2) \ , \ (2 \ ; \ -2) \ , \ (2 \ ; \ 2)$

Answer 2

Ответ:

x1=2

х2=-2

y1=2 y2=-2

24 варианта расписаний

Объяснение:

х^2+y^2=8

x^2-y^2=0

2x^2=8

x^2=4

x1=2 ⇒ 2^2+ y^2=8 y^2=4 ⇒y1=2 y2=-2

и х2=-2 ⇒ (-2^2)+ y^2=8 ⇒y1=2 y2=-2