Question

ДОПОМОЖIТЬ БУДЬ лАСКА

Answer 1

Ответ:

Объяснение:

5)

$\displaystyle \\1)\quad \frac{b^2+36p^2}{b-6p} +\frac{12bp}{6p-b} =\frac{b^2+36p^2}{b-6p} -\frac{12bp}{b-6p}=\frac{b^2-12bp+36p^2}{b-6p} =\\\\\\=\frac{(b-6p)^2}{b-6p} =b-6p$

$\displaystyle\\ 6) \quad \frac{56x^3y^4}{z^5} *\bigg(-\frac{x^2z^4}{16y^6} \bigg)=-\frac{56x^3y^4*x^2z^4}{z^5+16y^6} =-\frac{7x^5}{2zy^2}$

$\displaystyle \\7)\quad \frac{3b-3c}{c} :\frac{b^2-c^2}{4c^2} =\frac{3(b-c)}{c} :\frac{(b-c)(b+c)}{4c^2} =\frac{3(b-c)*4c^2}{c(b-c)(b+c)} =\\\\\\=\frac{12c}{b+c}$

$\displaystyle \\\\8)\quad \frac{m^2}{m^2-9} -\frac{m}{m+3} =\frac{m^2}{(m-3)(m+3)} -\frac{m}{m+3} ^{\setminus m-3}=\frac{m^2-m^2+3m}{(m-3)(m+3)} =\\\\\\= \frac{3m}{(m-3)(m+3)} =\frac{3m}{m^2-9}$