Question

Допоможіть будь ласка, треба з розрахунками

Answer 1

Ответ:

$\displaystyle \frac{1}{5}$

Объяснение:

$\displaystyle \frac{m}{n}=\frac{1}{2}\\\\n=2m\\\\\frac{4m^2+2mn-n^2}{8m^2+3n^2}=\frac{4m^2+2m(2m)-(2m)^2}{8m^2+3\cdot(2m)^2}=\\\\\\\frac{4m^2+4m^2-4m^2}{8m^2+3\cdot(4m^2)}=\frac{4m^2}{8m^2+12m^2}=\\\\\\\frac{4m^2}{20m^2}=\frac{1}{5}$