Question

Спрости вираз б) (2/3а²-1 1/6а)+(-1/6а²-3/4а+1)-(1-1/2а²)

Answer 1

Відповідь:

(2/3а² - 1 1/6а) + (-1/6а² - 3/4а + 1) - (1 - 1/2а²) =

2/3а² - 1 1/6а - 1/6а² - 3/4а + 1 - 1 + 1/2а² =

(2/3а² - 1/6а² + 1/2а²) + (-1 1/6а - 3/4а) + (1 - 1) =

(4/6а² - 1/6а² + 3/6а²) + (-1 2/12 - 9/12а) + 0 =

6/6а² + (-1 11/12а) = а² - 1 11/12а

Answer 2

Відповідь: а² 1 11/12 а.

(2/3а²-1 1/6а)+(-1/6а²-3/4а+1)-(1-1/2а²)=

2/3а²-1 1/6а-1/6а²-3/4а+1-1+1/2а²=

(2/3-1/6+1/2)а²-(1 1/6+3/4)а =

(4-1+3)/6 а²- 1 11/12 а=

а²-1 11/12а.