Question

8x⁴/x² - 4 × x+2/4x²

Answer 1

Ответ:

$\frac{8x {}^{4} }{x {}^{2} } - 4x + \frac{2}{4x {}^{2} } = \frac{32x {}^{4} + 2 - 16x {}^{3} }{4x {}^{2} } = 8x {}^{2} + \frac{1}{x {}^{2} } - 4x$