Question

Решить задания 272, 274 даю 50 баллов ОЧЕНЬ СРОЧНО

Answer 1

№272

$a)a(2a + 3) = a \times 2a + 3a = 2a {}^{2} + 3a$

$б)3x(x {}^{2} - 4x + 3) = 3x \times x {}^{2} - 3x \times 4x + 3x \times 3 = 3x {}^{3} - 12x {}^{2} + 9x$

$в) - 2b(b {}^{2} + 2b - 3) = - 2b \times b {}^{2} - 2b \times 2b - 2b \times ( - 3) = - 2b {}^{3} - 4b {}^{2} + 6b$

$г)3c {}^{2} ( - 2c {}^{4} + c {}^{2 } + 3) = - 3c {}^{2} \times 2c {}^{4} + 3c {}^{2} \times c {}^{2} + 3c {}^{2} \times 3 = - 6c {}^{6} + 3c {}^{4} + 9c {}^{2}$

$д)( - 3n {}^{2} + 2n) \times 2n = - 6n {}^{3} + 4n {}^{2}$

$е)(2a {}^{2} - 2a - 5) \times ( - 3a) = - 2a {}^{2} \times 3a - 2a \times ( - 3a) - 5 \times ( - 3a) = - 6a {}^{3} + 6a {}^{2} + 15a$

№274

$a)c(c {}^{2} + 3c) - 3c { }^{2} = c {}^{3} + 3c {}^{2} - 3c {}^{2} = c {}^{3}$

$б) - 5x(x {}^{2} + 3x - 4) - 20x = - 5x {}^{3} - 15x {}^{2} + 20x - 20x = - 5x {}^{3} - 15x {}^{2}$

$в)2a(3a - 4b) + 8ab - 2a {}^{2} = 6a {}^{2} - 8ab + 8ab - 2a {}^{2} = 4a {}^{2}$

$г) - 4ab + 2a(2b + 3) - 6a = - 4ab + 4ab + 6a - 6a = 0$

Answer 2

№272

Объяснение:

а) а(2а+3)=а×2а+3=2а²+3а=> Отв: 2а²+3а

б)3х(х²-4х+3)=3х×х²-3х×4х+3х+3=3х³-12х²+9х=> отв: 3х³-12х²+9х

в)-2b(b²+2b-3)=-2b×b²-2b×2b×(-3)=-2b³-4b²+2b×3 т. е. 6b, => отв: -2b³-4²+6b

г) 3с²(-2с⁴+с²+3)=-3с²×2с⁴+3с²×с²+3с²×3=-6с⁶+3с⁴+9с²=> отв: -6с⁶+3с⁴+9с²

д)(-3n²+2n)×2n=-6n³+4n²=> Отв:-6n³+4n²

е)(2а²-2в-5)×(-3а)=-2а²×3а-2а×(-3а)-5×(-3а)=-6а³+6а²+15а=> Отв: -6а³+6а²+15а.

Объяснение:

№274 по фото: